q=100+4q+q^2

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Solution for q=100+4q+q^2 equation: 



q=100+4q+q^2

We move all terms to the left:

q-(100+4q+q^2)=0

We get rid of parentheses

-q^2-4q+q-100=0

We add all the numbers together, and all the variables

-1q^2-3q-100=0

a = -1; b = -3; c = -100;
Δ = b2-4ac
Δ = -32-4·(-1)·(-100)
Δ = -391
Delta is less than zero, so there is no solution for the equation

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